I have game idea, please make it for me...

[Beherith]

sqrt(2)/2

[SinbadEV]

sqrt(2)/2

oops... I didn't notice you post... I worked it out to r.sqrt(3) which was right (my circles have a radius of 50 and the offset of each row is ~86.6 so I've used 87)...
and I don't see what "sqrt(2)/2" is supposed to mean... where's the variable?

[Beherith]

whoops, my bad, it is sqrt(3). Height of equilateral triangle. so the answer is sqrt(3). You get no variable because you asked for ratio.

[zwzsg]

what is the ratio of vertical offset to radius for the second row in a hexagonal latice?

Ambigious question.

1) What kind of hexagonal lattice? There are two non-retarded orientations:

Do you mean:



Or




2) Which second row do you mean? The second row that is vertically aligned, or the second row that closer but shifted?



Or




The answers are 5/2, 3/2, sqrt(3), sqrt(3)/2.

where's the variable?

You asked for a ratio. For the ratio h/r. So there is no r. Ask about h expressed in function of r if that is what you want.

[SinbadEV]

Now I feel bad for having figured it out before people gave me intelligent responses... thanks for the effort anyways... and @zwzsg since you know what I'm talking about, do any of the mentioned numbers come out to finite ratios for the "closer but horizontally offset next row"?

also, I had forgotten I was asking for a ratio... I get it now.

edit and attachment:
This is the grid I'm using right now...

To move around the grid you have 6 directions
NW = Up
NE = Up-Right
E = Right
SE = Down
SW = Down-Left
W = Left

[SinbadEV]

In case you were wondering how freaking fast javascript is, check out my test page... it does the following every time you move your mouse:

Code: Select all

		function intersects(x, y, cx, cy, r) {
			dx = x-cx
			dy = y-cy
			return dx*dx+dy*dy <= r*r
		}

		function mouseMove(e)
		{
			var mouseX=0, mouseY=0;

			if(e.offsetX) {
				mouseX = e.offsetX;
				mouseY = e.offsetY;
			}
			else if(e.layerX) {
				mouseX = e.layerX;
				mouseY = e.layerY;
			}

			/* do something with mouseX/mouseY */
			var coords=document.getElementById("coords");
			coords.innerHTML = mouseX+", "+mouseY;
			var found = false;
			for (x=0;x<x_cols;x++) {
				for (y=0;y<y_rows;y++) {
					
					cxt.fillStyle="#000000";
					coordText = "("+x+","+y+")";
					metrics = cxt.measureText(coordText)
					wo = Math.floor(metrics.width/2);
					if (intersects(mouseX,mouseY,x*2*r+r+(y*r),y*o+r, r) && !found) {
						data.innerHTML = x+", "+y;
						found = true;
					}
					
				}
			}
			if (!found) {data.innerHTML = "none"};
		}

and there is no perceptible lag

edit: and don't bother pointing out that a bunch of the stuff it's doing is redundant... I've fixed it, it looks like this now

Code: Select all

		function intersects(x, y, cx, cy, r) {
			dx = x-cx
			dy = y-cy
			return dx*dx+dy*dy <= r*r
		}

		function mouseMove(e)
		{
			var mouseX=0, mouseY=0;

			if(e.offsetX) {
				mouseX = e.offsetX;
				mouseY = e.offsetY;
			}
			else if(e.layerX) {
				mouseX = e.layerX;
				mouseY = e.layerY;
			}

			/* do something with mouseX/mouseY */
			coords.innerHTML = mouseX+", "+mouseY;
			var found = false;
			for (x=0;x<x_cols;x++) {
				for (y=0;y<y_rows;y++) {
					if (intersects(mouseX,mouseY,x*2*r+r+(y*r),y*o+r, r) && !found) {
						data.innerHTML = x+", "+y;
						found = true;
					}
					
				}
			}
			if (!found) {data.innerHTML = "none"};
		}

[Caydr]

How many of these threads have you made, Sinbad? You're making me feel inadequate.

[PicassoCT]

This one is diffrent, he contributed java-code, the usual un-productive pingpong and trolling ended for a moment. Sinbad can do it, i see contribooty. If its good i have the right to steal it.

[SinbadEV]

due to popular demand I have have shifted my place for posting of crazy ideas to http://sinbadev-benjie.blogspot.com/