Appreciation...
Moderator: Content Developer
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Appreciation...
It's surprising how little a lot of people appreciate the DGUN...
The ultimate force, that destroys anything...
And how... Doomed... The targets must feel.
Here are some screenshots showing my interpretation of it. Also, is there any way to hide the HUD that you see when in FPS mode?
The ultimate force, that destroys anything...
And how... Doomed... The targets must feel.
Here are some screenshots showing my interpretation of it. Also, is there any way to hide the HUD that you see when in FPS mode?
- CarRepairer
- Cursed Zero-K Developer
- Posts: 3359
- Joined: 07 Nov 2007, 21:48
Re: Appreciation...
Not surprising at all considering the double dgun is twice as strong. Makes the regular dgun look like a joke.Blue_Falcon wrote:It's surprising how little a lot of people appreciate the DGUN...
The ultimate force, that destroys anything...
By the way you should have put this in the BA forum.
Re: Appreciation...
I propose doubling the damage of the dgun. Also, your "interpretations" are wrong.
- bobthedinosaur
- Blood & Steel Developer
- Posts: 2702
- Joined: 25 Aug 2004, 13:31
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
OK... Please move this...
Nobody appreciates my appreciation topic... How sad
Nobody appreciates my appreciation topic... How sad

Re: Appreciation...
Nonsense. I appreciate dgun very much D:Blue_Falcon wrote:OK... Please move this...
Nobody appreciates my appreciation topic... How sad
Re: Appreciation...
I appreciate this thread and BA is not the only mod with the DGUN in it.
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
Yeah, but I guess this should be in the BA forum, as it was made in BA.
Re: Appreciation...
poor little flea :'(
double dgun is just as powerful as normal dgun, i can prove this
a = dgun
a = b * a
a(squared) = (a)(b) - b(squared)
a(squared) - b(squared) = (a)(b) - b(squared) factor
(a+b)(a-b) = b(a-b) /(a-b)
a+b = b since b = a
a+a = a
2a = a
therefore double dgun = dgun
:D
double dgun is just as powerful as normal dgun, i can prove this
a = dgun
a = b * a
a(squared) = (a)(b) - b(squared)
a(squared) - b(squared) = (a)(b) - b(squared) factor
(a+b)(a-b) = b(a-b) /(a-b)
a+b = b since b = a
a+a = a
2a = a
therefore double dgun = dgun
:D
Re: Appreciation...
Silly wannabe mathematician!
You can't write a proof without stating logic for every step!
Unless you're lurker.
You can't write a proof without stating logic for every step!

Unless you're lurker.
Re: Appreciation...
wow, I'm in envy of your ability to make almost every step when writing a proof a failure, but still confuse people who don't know what they're looking for
edit: the only way to make that proof work requires dividing by zero?
edit: the only way to make that proof work requires dividing by zero?
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
A lot more correct (and more simple) is:
DGUN=Ôê×
2Ôê× = Ôê×
therefore 2DGUN=DGUN
Now, who will dare argue against this?
DGUN=Ôê×
2Ôê× = Ôê×
therefore 2DGUN=DGUN
Now, who will dare argue against this?

Re: Appreciation...
I never say this, but you're all dorks.
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
Wait, are you criticizing me of taking a joke too seriously? I'm only going along with it.
And can someone please move this...
EDIT: Thanks.
And can someone please move this...
EDIT: Thanks.

- TheFatController
- Balanced Annihilation Developer
- Posts: 1177
- Joined: 10 Dec 2006, 18:46
Re: Appreciation...
Mods need to move threads into the BA forum before they fill up with outsiders posts imo :p
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
Yeah... Now, nobody's posted anything completely on-topic in this thread >.>. Someone please state their opinion on it.
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
Bump, someone please state their opinion on these screens 

Re: Appreciation...
you can reference the coefficient of infinity as density, thus making two times infinity not the same as infinityBlue_Falcon wrote:A lot more correct (and more simple) is:
DGUN=Ôê×
2Ôê× = Ôê×
therefore 2DGUN=DGUN
Now, who will dare argue against this?
- Blue_Falcon
- Posts: 155
- Joined: 16 Oct 2008, 18:54
Re: Appreciation...
aw, I didn't mean on my maths... I meant on the screens. And what you said is wrong, because it disproves my theory. Who cares if I understand it?aegis wrote:you can reference the coefficient of infinity as density, thus making two times infinity not the same as infinityBlue_Falcon wrote:A lot more correct (and more simple) is:
DGUN=Ôê×
2Ôê× = Ôê×
therefore 2DGUN=DGUN
Now, who will dare argue against this?


So, do you have anything to say about the screens?
Re: Appreciation...
i will since dgun isnt infinity damage and you can dgun a jugg and not kill it if you only graze itBlue_Falcon wrote:A lot more correct (and more simple) is:
DGUN=Ôê×
2Ôê× = Ôê×
therefore 2DGUN=DGUN
Now, who will dare argue against this?