i just riddled out to find the Perfect amount of Metall for any kind of Map. And this is were i need your help. I always lost in Math...Well here are some Facts i extracted out of RiverDale - divided it by a Line along the "Standard Front" the Line were the Battle gets porcy - it is the Ballance Point of two equall Oponents - till the Berthas have a go.
The Upper half had (near the StandardFront Metallspots didn`t count)
Normal Mexes - 46 Metall
Moho Mexes 161
The Line was about 200 Dragons Teeth long.
(I used DragonsTeeth as Unit)
2/3 of it were "EasyDefense" Territory. 1/3 was the Assault route. I assumed for my first attempt on the Formula That the Assault Line needs about 4/5 of the Metallbudget.
Therefore i assumed: 1/5 of the Metallbudget (e.g. 161:5=32.2 Moho is needed) for a Defenseline 133 Dragons long.
In Total for Defense. A Dragon Teeth Space Defenseline needs 0.24210 Mohometall.
4/5 of the Metall (remaining 129 Mohometall) are needed for the Assaultpart of the line. The Assaultpart was assumed to be 67 Dragons Teeth long (and consisted of the Chockepoints of the Line)
In Total for Assault a DragonTeeth Unit has 0.5193 Mohometall.
Formula this far: Amount of Total Metall in the Map y
y= 2{[(x*1/5) * Number of DefenfenseDragon] * [(x*4/5) * Number of OffensiveDragonteeth]}
x= Metallquote ?
This doesen`t say anything about Metall Placement. It is just a Try to calculate something, i don`t get along with otherwise. I also know, that some Units don`t fit into the Formula (spidermines, Spiderk-bots, Krogoths) Also Mohometallmakers are not Touched by this. Does this point into the right direction ?
Me needs you help...